In an isosceles triangle $ABC$, $cos(A)=\frac{12}{13}$ and $cos(B)=-0.70$. What is the value of $sin(C)$ in simplified fraction?
Answer:
Answer:
5/13
Explanation
The correct answer is $\frac{5}{13}$
Draw a diagram for the right-angled triangle as described in the question and then find $sin(C)$.
✨ Expert's Tip ✨
An angle is greater than $90°$ and less than $270°$ when the cosine of the angle is negative, based on unit circle trigonometry.