The graphs of the equations in the given system of equations intersect at a point in the $xy$-plane. What is the possible value of $c$?
$$6x-3y=4$$
$$6y=-3x^2+c$$
Answer:
-20
Explanation
The correct answer is $-20$.
Substitute $y$ from the first equation into the second equation and then find $c$ for which there is exactly one intersecting point between the equations.
✨ Expert's Tip ✨
A quadratic equation has no real root if the discriminant, $D=b^2-4ac$, is less than zero.
